27092cabc4
Comparing PkgVersion and Version objects can produce nonsensical
results. For example, equality is not symmetric:
irb(main):002:0> PkgVersion.new("1.0", 0) == Version.new("1.0")
=> false
irb(main):003:0> Version.new("1.0") == PkgVersion.new("1.0", 0)
=> true
Rather than attempt to deal with subclass-superclass equality, let's use
composition and punt on the problem altogether.
46 lines
775 B
Ruby
46 lines
775 B
Ruby
require "version"
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class PkgVersion
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include Comparable
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RX = /\A(.+?)(?:_(\d+))?\z/
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def self.parse(path)
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_, version, revision = *path.match(RX)
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version = Version.new(version)
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new(version, revision.to_i)
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end
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def initialize(version, revision)
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@version = version
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@revision = version.head? ? 0 : revision
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end
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def head?
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version.head?
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end
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def to_s
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if revision > 0
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"#{version}_#{revision}"
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else
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version.to_s
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end
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end
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alias_method :to_str, :to_s
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def <=>(other)
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return unless PkgVersion === other
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(version <=> other.version).nonzero? || revision <=> other.revision
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end
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alias_method :eql?, :==
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def hash
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version.hash ^ revision.hash
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end
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protected
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attr_reader :version, :revision
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end
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