Remove GraphQL debug output

Let's get this ready to go since we don't want to accidentally leak
private information.
This commit is contained in:
Carlo Cabrera 2024-08-30 10:45:19 +08:00
parent 1d71ee8f16
commit cabbb0b8e3
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@ -334,7 +334,6 @@ module GitHub
def self.open_graphql(query, variables: nil, scopes: [].freeze, raise_errors: true)
data = { query:, variables: }
result = open_rest("#{API_URL}/graphql", scopes:, data:, request_method: "POST")
odebug "GraphQL Query Response", result
if raise_errors
if result["errors"].present?