Fix some #eql? correctness issues
The implementation of #eql? and #hash should ensure that if a.eql?(b), then a.hash == b.hash, but #eql? itself should not *depend* on #hash. For example, given class Thingy def eql? instance_of?(other.class) && hash == other.hash end def hash [name, *tags].hash end end if #hash produces a collision for different values of [name, *tags], two Thingy objects will appear to be eql?, even though this is not the case. Instead, #eql? should depend on the equality of name and tags directly.
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@ -21,7 +21,7 @@ class Dependency
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end
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def eql?(other)
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instance_of?(other.class) && hash == other.hash
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instance_of?(other.class) && name == other.name
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end
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def hash
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@ -20,7 +20,7 @@ class Option
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end
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def eql?(other)
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other.is_a?(self.class) && hash == other.hash
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instance_of?(other.class) && name == other.name
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end
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def hash
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@ -54,7 +54,7 @@ class Requirement
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end
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def eql?(other)
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instance_of?(other.class) && hash == other.hash
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instance_of?(other.class) && name == other.name && tags == other.tags
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end
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def hash
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@ -121,4 +121,18 @@ class RequirementTests < Test::Unit::TestCase
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req.to_dependency.modify_build_environment
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end
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end
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def test_eql
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a, b = Requirement.new, Requirement.new
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assert a.eql?(b)
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assert b.eql?(a)
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assert_equal a.hash, b.hash
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end
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def test_not_eql
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a, b = Requirement.new([:optional]), Requirement.new
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assert_not_equal a.hash, b.hash
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assert !a.eql?(b)
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assert !b.eql?(a)
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end
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end
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